How to Calculate the Area of Any Quadrilateral: A Step-by-Step Guide

If you're stuck on your geometry homework trying to figure out the area of a quadrilateral, you've come to the right place! Remember—the "area" of a shape is just how much 2-dimensional space it takes up. For some quadrilaterals, there's a handy formula you can use to calculate the area. But what if all the sides are different? Just divide it into triangles! Read on to follow along with some examples and see how this works.

Calculating the Area of a Quadrilateral

Find the area of any quadrilateral by dividing it into 2 triangles. Then, find the area of each of those triangles using the formula $A={\frac {1}{2}}bh$ (Area = 1/2 base times height) and add them together.

Area of Square, Rectangle, and Rhombus Cheat Sheets

Area of a Square Diagram

Area of a Rectangle Diagram

Area of a Rhombus Diagram

Area of Trapezoid and Kite Cheat Sheets

Area of a Trapezoid Diagram

Area of a Kite Diagram

Section 1 of 7:

Square

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Use $A=s^{2}$ to find the area of a square. In the formula, "s" is the length of one side. Since all sides are equal, you only need the length of one of them to quickly find the area of any square. Then, express the area in units squared.
- For example, if you have a square and the length of one side is $4m$ , you would multiply $4*4$ to get $16m^{2}$ .
- Try it with a square that has sides $2in$ long. Just multiply $2*2$ . That square has an area of $4in^{2}$ . No matter what the unit is, it's always squared when you're talking about the area.

Section 2 of 7:

Rectangle

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Use the formula $A=lw$ to find the area of a rectangle. Since a rectangle has sides of 2 different lengths, you multiply one value by the other to find out how much space the rectangle covers. Just get the length of one of the short sides and one of the long sides.
- For example, if your rectangle has a length of $8m$ and a width of $2m$ , your equation would be $A=8*2$ , which gives you an answer of $A=16m^{2}$ .
- What if your rectangle has bigger numbers? The formula still works the same way. For example, a rectangle with a length of $1762km$ and a width of $288km$ would have an area of $A=1762*288=507,456km^{2}$ .

Section 3 of 7:

Parallelogram

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$Find the area of a parallelogram with A = b h {\displaystyle A=bh} .$
Find the area of a parallelogram with $A=bh$ . A parallelogram has 2 parallel sides—those are the bases (b). The height (h) is the distance from one base to the other. Multiply those 2 values together and you've got the area of a parallelogram.^{[1]
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- For example, say you have a parallelogram with a base length of $4m$ and a height of $2m$ . Plug your numbers into the equation $A=bh$ to get $A=4*2$ , then simplify to find an area of $8m^{2}$ .
- Remember: the height isn't the same as the length of the side! It's the straight-line distance between the top and bottom bases.

Section 4 of 7:

Trapezoid

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Use $A={\frac {b_{1}+b_{2}}{2}}*h$ to calculate a trapezoid's area. Since the 2 bases (b) of a trapezoid aren't the same length, the average is used for the area of this shape. Once you have the average length of the two bases, multiply that by the height (h)—the distance between the two bases—to easily find the area of a trapezoid.^{[2]
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- For example, say you've got a trapezoid with a bottom side of $5m$ , a top side of $3m$ , and a height of $6$ . Start by adding the length of the two bases: $5+3=8$ . Then, divide by $2$ to get the average length of the bases: $4$ .
- You've taken care of the first part of the formula! Now all you have to do is multiply the average length of the bases, $4$ , by the height, $6$ : $4*6=24$ . The area of your trapezoid is $24m^{2}$ .

Section 5 of 7:

Rhombus

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Get the area of a rhombus with $A={\frac {(d_{1}*d_{2})}{2}}$ . In this formula, $d_{1}$ $d_{1}$ and $d_{2}$ $d_{2}$ refer to the length of 2 diagonal lines that you'll draw inside the shape between the opposite corners. Get the length of each of those 2 diagonals, multiply them together, then divide by 2. You've got the area of a rhombus!^{[3]
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- For example, say you have a rhombus with diagonals of $9m$ and $4m$ . You know that $9x4=36$ . Divide $36$ by $2$ . The area of your rhombus is $18m^{2}$ .
- What if the product of the diagonals is an odd number? No problem, just express your answer as a decimal. For example, a rhombus with diagonals of $3cm$ and $7cm$ has an area of $A={\frac {(3*7)}{2}}={\frac {21}{2}}=10.5cm^{2}$ .

Section 6 of 7:

Kite

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Find the area of a kite with $A={\frac {(d_{1}*d_{2})}{2}}$ . A kite's orientation can throw you off because your "diagonal" lines (d1 and d2) might not look diagonal at all—they might actually be vertical and horizontal. But as long as they're connecting opposing corners, they're still called diagonals. Multiply them together and then divide by $2$ $2$ to get your area.
- For example, say you have a kite with diagonals of $4m$ and $12m$ . Plug those values into the formula: $A={\frac {(4*12)}{2}}={\frac {48}{2}}=24$ . The area of your kite is $24m^{2}$ .

Section 7 of 7:

Any Quadrilateral Shape

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1
Divide the quadrilateral into 2 triangles. If you draw a diagonal line from one corner to the other, you create 2 triangles within the quadrilateral. The 2 triangles might not be the same size, but they share a common base—the diagonal that divides the quadrilateral.^{[4]
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- If you're working on a homework problem, the diagonal line might already be drawn for you. In fact, if you have a quadrilateral with a diagonal line, that's a pretty big clue that you'll use triangles to find the area.
2
Get the measurements for the base and heights of your triangles. To find the area of a triangle, you need to know the size of the base (b) and the height (h). Your diagonal line is serving as the base of your triangles, so they'll both have the same measurement for the base. They might not be the same height, though, depending on the quadrilateral. The height isn't the length of a side (unless you're working with a right triangle). It's the length from the base to the top point of the triangle.^{[5]
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- If you're working a problem for homework and you're not given any way to measure these values, you can't use triangles to find the area of that quadrilateral.
3
Find the area of each triangle. Recall that the formula for the area of a triangle is $A={\frac {1}{2}}bh$ $A={\frac {1}{2}}bh$ . All you have to do is plug in the measurements you got for the base and the height, then simplify the equation to find the area of each triangle.^{[6]
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- For example, say you have a diagonal with a length of $4$ that forms 2 triangles that each have a height of $2$ . Your formula would be $A={\frac {1}{2}}(4)(2)$ , which simplifies to $A={\frac {1}{2}}(8)$ . So your answer would be $A=4$ .
- In this example, both triangles have the same area since they both have the same base and height.
4
Add the areas of the 2 triangles together to get the area of the quadrilateral. Since you originally divided your quadrilateral into 2 triangles, all you have to do is add those 2 areas together and you'll have the total area of the quadrilateral. You could also think of the area of one of the triangles as being half the area of the quadrilateral.^{[7]
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- To return to the previous example, since each triangle has an area of $4$ , you would simply add $4+4$ to get $8$ .
- Area is always expressed in square units. If the measurements in your original problem were meters, your answer would be $8m^{2}$ .

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Could I divide the quadrilateral into two triangles, find the area of each, and add them to find the area of the quadrilateral?

Donagan

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Yes. If you know the base and height of each triangle, you can just add the two areas together. It's not always possible, however, to know the bases and heights.

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How do I calculate the area of a parallelogram?

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Calculate as follows: Area = base multiplied by height.

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How would I know the angle for quadrilateral?

Donagan

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Assuming you're not given the angle(s), you either have to use a protractor or analyze the quadrilateral and use trigonometry.

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Since a square is also a rhombus, if you only know the measurement of a diagonal, you can also find the area of a square using the rhombus formula.

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