This article was reviewed by Joseph Meyer. Joseph Meyer is a High School Math Teacher based in Pittsburgh, Pennsylvania. He is an educator at City Charter High School, where he has been teaching for over 7 years. Joseph is also the founder of Sandbox Math, an online learning community dedicated to helping students succeed in Algebra. His site is set apart by its focus on fostering genuine comprehension through step-by-step understanding (instead of just getting the correct final answer), enabling learners to identify and overcome misunderstandings and confidently take on any test they face. He received his MA in Physics from Case Western Reserve University and his BA in Physics from Baldwin Wallace University.
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Have you ever had a simultaneous problem equation you needed to solve? When you use the elimination method, you can achieve a desired result in a very short time. This article can explain how to perform to achieve the solution for both variables.
Steps
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Write down both of the equations that you'll need to solve.[1]
- 3x - y = 12
- 2x + y = 13
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Number the equations. 3x - y = 12 as number one, and 2x + y = 13 as number two.[2]Advertisement
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Check if both equations have the same variable/unknown term in them.[3]
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Look for signs of the unknown variables or terms. Remember subtraction can also be referred to as the addition of a negative number. If the signs are the same, subtract both equations. If they are different then add the equations.[4]
- 3x - y = 12
- + 2x + y = 13
- -------------
- 5x = 25
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Solve to find the first unknown variable from the resulting (rather shortened) equation. Divide both sides by the coefficient of the left side. Take 5 to the other side.It will look like this:x = 25/5.[5]
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25 divided by 5 makes 5 so we have now found the value of "x" which is 5.
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Find the value of "y". Use the value of x that was obtained above into either equation (but stick with this equation for the time being). Substitute this value of x into the equation.[6]
- 3x - y = 12
- 3(5)-y = 12
- 15 - y = 12
- - y = 12 - 15
- - y = - 3(divide both sides by negative one, will be able to cut both signs)
- y = 3
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Check the problem. Substitute both the values into the other equation. If the two side numbers at the very end equal each other, you've correctly solved this system of simultaneous equations.[7]
- 3x - y = 12
- 3(5) - 3 = 12
- 15 - 3 = 12
- 12 = 12
Community Q&A
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QuestionHow do I find the first term and the constant difference of simultaneous equations?DonaganTop Answerer"First term" and "constant difference" do not apply to simultaneous equations. (They are used in arithmetic sequences.)
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QuestionIs this useful in all the countries? Where I live, we work our equations very differently.DonaganTop AnswererMathematics knows no national boundaries. There is more than one method of solving simultaneous equations, and all methods are known and "useful" in every country. Apparently you were not taught the elimination method in school.
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QuestionHow do I work with fractions in solving simultaneous equations using elimination method?DonaganTop AnswererThe process is the same as outlined above, except that you would have to clear a fraction when solving for a variable. For example, you may see something like 5x/2 = 10, in which case you would just multiply both sides of that equation by 2 and then divide both sides by 5.
Tips
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You can solve it horizontally as well.Thanks
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Remember that if the unknown terms have the same signs you must subtract and if they have different signs you must add the equations.Thanks
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The easiest of all is the elimination method and fastest as well. It is simple and can be learned much more easily then the other two. It is usually used when the equations have the same variable/unknown term disregarding the sign.Thanks
References
- ↑ https://flexbooks.ck12.org/cbook/ck-12-cbse-math-class-10/section/3.6/primary/lesson/solving-simultaneous-linear-equations-by-elimination/
- ↑ https://www.youtube.com/watch?v=O-rrOPPmFgM
- ↑ https://www.youtube.com/watch?v=7Ja_H6a8ltY
- ↑ https://www.mathsteacher.com.au/year10/ch04_simultaneous/03_elimination_method/elim.htm
- ↑ https://www.bbc.co.uk/bitesize/guides/z9y9jty/revision/1
- ↑ https://www.bbc.co.uk/bitesize/guides/z9y9jty/revision/1
- ↑ https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:systems-of-equations/x2f8bb11595b61c86:solving-systems-elimination/a/elimination-method-review
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